Bar element functions¶
Bar elements are available for one, two, and three dimensional analysis.
bar1e |
Compute element matrix |
bar1s |
Compute normal force |
bar1we |
Compute element matrix for bar element with elastic support |
bar1ws |
Compute normal force for bar element with elastic support |
bar2e |
Compute element matrix |
bar2s |
Compute normal force |
bar2ge |
Compute element matrix for geometric nonlinear element |
bar2gs |
Compute normal force for bar element with elastic support |
bar3e |
Compute element matrix |
bar3s |
Compute normal force |
bar1e¶
Ke = bar1e(ex, ep)
[Ke, fe] = bar1e(ex, ep, eq)
- Description:
bar1eprovides the element stiffness matrix \(\bar{\mathbf{K}}^e\) for a one dimensional bar element. The input variablesex\(= [x_1 \;\; x_2]\) \(\qquad\)ep\(= [E \; A]\)supply the element nodal coordinates \(x_1\) and \(x_2\), the modulus of elasticity \(E\), and the cross section area \(A\).
The element load vector \(\bar{\mathbf{f}}_l^e\) can also be computed if a uniformly distributed load is applied to the element. The optional input variable
eq\(= [q_{\bar{x}}]\)contains the distributed load per unit length, \(q_{\bar{x}}\).
- Theory:
The element stiffness matrix \(\bar{\mathbf{K}}^e\), stored in
Ke, is computed according to\[\begin{split}\bar{\mathbf{K}}^e = \frac{D_{EA}}{L} \begin{bmatrix} 1 & -1 \\ -1 & 1 \end{bmatrix}\end{split}\]where the axial stiffness \(D_{EA}\) and the length \(L\) are given by
\[D_{EA} = EA; \quad L = x_2 - x_1\]The element load vector \(\bar{\mathbf{f}}_l^e\), stored in
fe, is computed according to\[\begin{split}\bar{\mathbf{f}}_l^e = \frac{q_{\bar{x}} L}{2} \begin{bmatrix} 1 \\ 1 \end{bmatrix}\end{split}\]
bar1s¶
es = bar1s(ex, ep, ed)
es = bar1s(ex, ep, ed, eq)
[es, edi] = bar1s(ex, ep, ed, eq, n)
[es, edi, eci] = bar1s(ex, ep, ed, eq, n)
- Description:
bar1scomputes the normal force in the one dimensional bar elementbar1e.The input variables
exandepare defined inbar1eand the element nodal displacements, stored ined, are obtained by the functionextract_ed. If distributed load is applied to the element, the variableeqmust be included.The number of evaluation points for normal force and displacement are determined by
n. Ifnis omitted, only the ends of the bar are evaluated.The output variables
es\(= \begin{bmatrix} N(0) \\ N(\bar{x}_2) \\ \vdots \\ N(\bar{x}_{n-1}) \\ N(L) \end{bmatrix}\) \(\qquad\)edi\(= \begin{bmatrix} u(0) \\ u(\bar{x}_2) \\ \vdots \\ u(\bar{x}_{n-1}) \\ u(L) \end{bmatrix}\) \(\qquad\)eci\(= \begin{bmatrix} 0 \\ \bar{x}_2 \\ \vdots \\ \bar{x}_{n-1} \\ L \end{bmatrix}\)contain the normal force, the displacement, and the evaluation points on the local \(\bar{x}\)-axis. \(L\) is the length of the bar element.
- Theory:
The nodal displacements in local coordinates are given by
\[\begin{split}\mathbf{\bar{a}}^e = \begin{bmatrix} \bar{u}_1 \\ \bar{u}_2 \end{bmatrix}\end{split}\]The transpose of \(\mathbf{\bar{a}}^e\) is stored in
ed.The displacement \(u(\bar{x})\) and the normal force \(N(\bar{x})\) are computed from
\[u(\bar{x}) = \mathbf{N} \mathbf{\bar{a}}^e + u_p(\bar{x})\]\[N(\bar{x}) = D_{EA} \mathbf{B} \mathbf{\bar{a}}^e + N_p(\bar{x})\]where
\[\mathbf{N} = \begin{bmatrix} 1 & \bar{x} \end{bmatrix} \mathbf{C}^{-1} = \begin{bmatrix} 1 - \frac{\bar{x}}{L} & \frac{\bar{x}}{L} \end{bmatrix}\]\[\mathbf{B} = \begin{bmatrix} 0 & 1 \end{bmatrix} \mathbf{C}^{-1} = \frac{1}{L} \begin{bmatrix} -1 & 1 \end{bmatrix}\]\[u_p(\bar{x}) = -\frac{q_{\bar{x}}}{D_{EA}} \left( \frac{\bar{x}^2}{2} - \frac{L\bar{x}}{2} \right)\]\[N_p(\bar{x}) = -q_{\bar{x}} \left( \bar{x} - \frac{L}{2} \right)\]in which \(D_{EA}\), \(L\), and \(q_{\bar{x}}\) are defined in
bar1eand\[\begin{split}\mathbf{C}^{-1} = \begin{bmatrix} 1 & 0 \\ -\frac{1}{L} & \frac{1}{L} \end{bmatrix}\end{split}\]
bar1we¶
- Purpose:
Compute element stiffness matrix for a one dimensional bar element with elastic support.
- Syntax:
Ke = bar1we(ex, ep)
[Ke, fe] = bar1we(ex, ep, eq)
- Description:
bar1weprovides the element stiffness matrix \(\bar{\mathbf{K}}^e\) for a one dimensional bar element with elastic support.The input variables
ex\(= [x_1\;\; x_2]\) \(\qquad\)ep\(= [E\; A\; k_{\bar{x}}]\)supply the element nodal coordinates \(x_1\) and \(x_2\), the modulus of elasticity \(E\), the cross section area \(A\) and the stiffness of the axial springs \(k_{\bar{x}}\).
The element load vector \(\bar{\mathbf{f}}_l^e\) can also be computed if a uniformly distributed load is applied to the element.
The optional input variable
eq\(= [q_{\bar{x}}]\)contains the distributed load per unit length, \(q_{\bar{x}}\).
Bar element with distributed load
- Theory:
The element stiffness matrix \(\bar{\mathbf{K}}^e\), stored in
Ke, is computed according to\[\bar{\mathbf{K}}^e = \bar{\mathbf{K}}^e_0 + \bar{\mathbf{K}}^e_s\]where
\[\begin{split}\bar{\mathbf{K}}^e_0 = \frac{D_{EA}}{L} \begin{bmatrix} 1 & -1 \\ -1 & 1 \end{bmatrix}\end{split}\]\[\begin{split}\bar{\mathbf{K}}^e_s = k_{\bar{x}} L \begin{bmatrix} \frac{1}{3} & \frac{1}{6} \\ \frac{1}{6} & \frac{1}{3} \end{bmatrix}\end{split}\]where the axial stiffness \(D_{EA}\) and the length \(L\) are given by
\[D_{EA} = EA; \qquad L = x_2 - x_1\]The element load vector \(\bar{\mathbf{f}}_l^e\), stored in
fe, is computed according to\[\begin{split}\bar{\mathbf{f}}_l^e = \frac{q_{\bar{x}} L}{2} \begin{bmatrix} 1 \\ 1 \end{bmatrix}\end{split}\]
bar1ws¶
es = bar1ws(ex, ep, ed)
es = bar1ws(ex, ep, ed, eq)
[es, edi] = bar1ws(ex, ep, ed, eq, n)
[es, edi, eci] = bar1ws(ex, ep, ed, eq, n)
- Description:
bar1wscomputes the normal force in the one dimensional bar elementbar1ws.The input variables
exandepare defined inbar1weand the element nodal displacements, stored ined, are obtained by the function_ed. If distributed load is applied to the element, the variableeqmust be included.The number of evaluation points for normal force and displacement are determined by
n. Ifnis omitted, only the ends of the bar are evaluated.The output variables are:
es\(= \begin{bmatrix} N(0) \\ N(\bar{x}_2) \\ \vdots \\ N(\bar{x}_{n-1}) \\ N(L) \end{bmatrix}\) \(\qquad\)edi\(= \begin{bmatrix} u(0) \\ u(\bar{x}_2) \\ \vdots \\ u(\bar{x}_{n-1}) \\ u(L) \end{bmatrix}\) \(\qquad\)eci\(= \begin{bmatrix} 0 \\ \bar{x}_2 \\ \vdots \\ \bar{x}_{n-1} \\ L \end{bmatrix}\)These contain the normal force, the displacement, and the evaluation points on the local \(\bar{x}\)-axis. \(L\) is the length of the bar element.
- Theory:
The nodal displacements in local coordinates are given by
\[\begin{split}\mathbf{\bar{a}}^e = \begin{bmatrix} \bar{u}_1 \\ \bar{u}_2 \end{bmatrix}\end{split}\]The transpose of \(\mathbf{\bar{a}}^e\) is stored in
ed.The displacement \(u(\bar{x})\) and the normal force \(N(\bar{x})\) are computed from
\[u(\bar{x}) = \mathbf{N} \mathbf{\bar{a}}^e + u_p(\bar{x})\]\[N(\bar{x}) = D_{EA} \mathbf{B} \mathbf{\bar{a}}^e + N_p(\bar{x})\]where
\[\mathbf{N} = \begin{bmatrix} 1 & \bar{x} \end{bmatrix} \mathbf{C}^{-1} = \begin{bmatrix} 1 - \frac{\bar{x}}{L} & \frac{\bar{x}}{L} \end{bmatrix}\]\[\mathbf{B} = \begin{bmatrix} 0 & 1 \end{bmatrix} \mathbf{C}^{-1} = \frac{1}{L} \begin{bmatrix} -1 & 1 \end{bmatrix}\]\[u_p(\bar{x}) = \frac{k_{\bar{x}}}{D_{EA}} \left[ \frac{\bar{x}^2 - L\bar{x}}{2} \quad \frac{\bar{x}^3 - L^2\bar{x}}{6} \right] \mathbf{C}^{-1} \mathbf{\bar{a}}^e - \frac{q_{\bar{x}}}{D_{EA}} \left( \frac{\bar{x}^2}{2} - \frac{L\bar{x}}{2} \right)\]\[N_p(\bar{x}) = k_{\bar{x}} \left[ \frac{2\bar{x} - L}{2} \quad \frac{3\bar{x}^2 - L^2}{6} \right] \mathbf{C}^{-1} \mathbf{\bar{a}}^e - q_{\bar{x}} \left( \bar{x} - \frac{L}{2} \right)\]in which \(D_{EA}\), \(L\), \(k_{\bar{x}}\) and \(q_{\bar{x}}\) are defined in
bar1weand\[\begin{split}\mathbf{C}^{-1} = \begin{bmatrix} 1 & 0 \\ -\frac{1}{L} & \frac{1}{L} \end{bmatrix}\end{split}\]
bar2e¶
Ke = bar2e(ex, ey, ep)
[Ke, fe] = bar2e(ex, ey, ep, eq)
- Description:
bar2eprovides the global element stiffness matrix \({\mathbf{K}}^e\) for a two dimensional bar element.The input variables
ex\(= [x_1 \;\; x_2]\) \(\qquad\)ey\(= [y_1 \;\; y_2]\) \(\qquad\)ep\(= [E \; A]\)supply the element nodal coordinates \(x_1\), \(y_1\), \(x_2\), and \(y_2\), the modulus of elasticity \(E\), and the cross section area \(A\).
The element load vector \({\mathbf{f}}_l^e\) can also be computed if a uniformly distributed load is applied to the element. The optional input variable
eq\(= [q_{\bar{x}}]\)contains the distributed load per unit length, \(q_{\bar{x}}\).
- Theory:
The element stiffness matrix \(\mathbf{K}^e\), stored in
Ke, is computed according to\[\mathbf{K}^e = \mathbf{G}^T \; \bar{\mathbf{K}}^e \; \mathbf{G}\]where
\[\begin{split}\bar{\mathbf{K}}^e = \frac{D_{EA}}{L} \begin{bmatrix} 1 & -1 \\ -1 & 1 \end{bmatrix} \qquad \mathbf{G} = \begin{bmatrix} n_{x\bar{x}} & n_{y\bar{x}} & 0 & 0 \\ 0 & 0 & n_{x\bar{x}} & n_{y\bar{x}} \end{bmatrix}\end{split}\]where the axial stiffness \(D_{EA}\) and the length \(L\) are given by
\[D_{EA} = EA; \qquad L = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\]and the transformation matrix \(\mathbf{G}\) contains the direction cosines
\[n_{x\bar{x}} = \frac{x_2 - x_1}{L} \qquad n_{y\bar{x}} = \frac{y_2 - y_1}{L}\]The element load vector \(\mathbf{f}_l^e\), stored in
fe, is computed according to\[\mathbf{f}_l^e = \mathbf{G}^T \; \bar{\mathbf{f}}_l^e\]where
\[\begin{split}\bar{\mathbf{f}}_l^e = \frac{q_{\bar{x}} L}{2} \begin{bmatrix} 1 \\ 1 \end{bmatrix}\end{split}\]
bar2s¶
- Purpose:
Compute normal force in a two dimensional bar element.
- Syntax:
es = bar2s(ex, ey, ep, ed)
es = bar2s(ex, ey, ep, ed, eq)
[es, edi] = bar2s(ex, ey, ep, ed, eq, n)
[es, edi, eci] = bar2s(ex, ey, ep, ed, eq, n)
- Description:
bar2scomputes the normal force in the two dimensional bar elementbar2e.The input variables
ex,ey, andepare defined inbar2eand the element nodal displacements, stored ined, are obtained by the functionextract_ed. If distributed loads are applied to the element, the variableeqmust be included. The number of evaluation points for section forces and displacements are determined byn. Ifnis omitted, only the ends of the bar are evaluated.The output variables
es\(= \begin{bmatrix} N(0) \\ N(\bar{x}_2) \\ \vdots \\ N(\bar{x}_{n-1}) \\ N(L) \end{bmatrix}\) \(\qquad\)edi\(= \begin{bmatrix} u(0) \\ u(\bar{x}_2) \\ \vdots \\ u(\bar{x}_{n-1}) \\ u(L) \end{bmatrix}\) \(\qquad\)eci\(= \begin{bmatrix} 0 \\ \bar{x}_2 \\ \vdots \\ \bar{x}_{n-1} \\ L \end{bmatrix}\)contain the normal force, the displacement, and the evaluation points on the local \(\bar{x}\)-axis. \(L\) is the length of the bar element.
- Theory:
The nodal displacements in global coordinates
\[\mathbf{a}^e = \begin{bmatrix} u_1 & u_2 & u_3 & u_4 \end{bmatrix}^T\]are also shown in
bar2e. The transpose of \(\mathbf{a}^e\) is stored ined.The nodal displacements in local coordinates are given by
\[\mathbf{\bar{a}}^e = \mathbf{G} \mathbf{a}^e\]where the transformation matrix \(\mathbf{G}\) is defined in
bar2e.The displacement \(u(\bar{x})\) and the normal force \(N(\bar{x})\) are computed from
\[u(\bar{x}) = \mathbf{N} \mathbf{\bar{a}}^e + u_p(\bar{x})\]\[N(\bar{x}) = D_{EA} \mathbf{B} \mathbf{\bar{a}}^e + N_p(\bar{x})\]where
\[\mathbf{N} = \begin{bmatrix} 1 & \bar{x} \end{bmatrix} \mathbf{C}^{-1} = \begin{bmatrix} 1-\frac{\bar{x}}{L} & \frac{\bar{x}}{L} \end{bmatrix}\]\[\mathbf{B} = \begin{bmatrix} 0 & 1 \end{bmatrix} \mathbf{C}^{-1} = \frac{1}{L} \begin{bmatrix} -1 & 1 \end{bmatrix}\]\[u_p(\bar{x}) = -\frac{q_{\bar{x}}}{D_{EA}}\left(\frac{\bar{x}^2}{2}-\frac{L\bar{x}}{2}\right)\]\[N_p(\bar{x}) = -q_{\bar{x}}\left(\bar{x}-\frac{L}{2}\right)\]where \(D_{EA}\), \(L\), \(q_{\bar{x}}\) are defined in
bar2eand\[\begin{split}\mathbf{C}^{-1} = \begin{bmatrix} 1 & 0 \\ -\frac{1}{L} & \frac{1}{L} \end{bmatrix}\end{split}\]
bar2ge¶
Ke = bar2ge(ex, ey, ep, Qx)
- Description:
bar2geprovides the element stiffness matrix \({\mathbf{K}}^e\) for a two dimensional geometric nonlinear bar element.The input variables
ex\(= [x_1 \;\; x_2]\) \(\qquad\)ey\(= [y_1 \;\; y_2]\) \(\qquad\)ep\(= [E \; A]\)supply the element nodal coordinates \(x_1\), \(y_1\), \(x_2\), and \(y_2\), the modulus of elasticity \(E\), and the cross section area \(A\).
The input variable
Qx\(= [Q_{\bar{x}}]\)contains the value of the axial force, which is positive in tension.
- Theory:
The global element stiffness matrix \(\mathbf{K}^e\), stored in
Ke, is computed according to\[\mathbf{K}^e = \mathbf{G}^T\,\mathbf{\bar{K}}^e\,\mathbf{G}\]where
\[\begin{split}\mathbf{\bar{K}}^e = \frac{D_{EA}}{L} \begin{bmatrix} 1 & 0 & -1 & 0 \\ 0 & 0 & 0 & 0 \\ -1 & 0 & 1 & 0 \\ 0 & 0 & 0 & 0 \end{bmatrix} + \frac{Q_{\bar{x}}}{L} \begin{bmatrix} 0 & 0 & 0 & 0 \\ 0 & 1 & 0 & -1 \\ 0 & 0 & 0 & 0 \\ 0 & -1 & 0 & 1 \end{bmatrix}\end{split}\]\[\begin{split}\mathbf{G} = \begin{bmatrix} n_{x\bar{x}} & n_{y\bar{x}} & 0 & 0 \\ n_{x\bar{y}} & n_{y\bar{y}} & 0 & 0 \\ 0 & 0 & n_{x\bar{x}} & n_{y\bar{x}} \\ 0 & 0 & n_{x\bar{y}} & n_{y\bar{y}} \end{bmatrix}\end{split}\]where the axial stiffness \(D_{EA}\) and the length \(L\) are given by
\[D_{EA} = EA \qquad L = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\]and the transformation matrix \(\mathbf{G}\) contains the direction cosines
\[n_{x\bar{x}} = n_{y\bar{y}} = \frac{x_2 - x_1}{L} \qquad n_{y\bar{x}} = -n_{x\bar{y}} = \frac{y_2 - y_1}{L}\]
bar2gs¶
- Purpose:
Compute axial force and normal force in a two dimensional bar element.
- Syntax:
[es, Qx] = bar2gs(ex, ey, ep, ed)
[es, Qx, edi] = bar2gs(ex, ey, ep, ed, n)
[es, Qx, edi, eci] = bar2gs(ex, ey, ep, ed, n)
- Description:
bar2gscomputes the normal force in the two dimensional bar elementsbar2ge.The input variables
ex,ey, andepare defined inbar2geand the element nodal displacements, stored ined, are obtained by the functionextract_ed. The number of evaluation points for section forces and displacements are determined byn. Ifnis omitted, only the ends of the bar are evaluated.The output variable
Qxcontains the axial force \(Q_{\bar{x}}\) and the output variableses\(= \begin{bmatrix} N(0) \\ N(\bar{x}_2) \\ \vdots \\ N(\bar{x}_{n-1}) \\ N(L) \end{bmatrix}\) \(\qquad\)edi\(= \begin{bmatrix} u(0) \\ u(\bar{x}_2) \\ \vdots \\ u(\bar{x}_{n-1}) \\ u(L) \end{bmatrix}\) \(\qquad\)eci\(= \begin{bmatrix} 0 \\ \bar{x}_2 \\ \vdots \\ \bar{x}_{n-1} \\ L \end{bmatrix}\)contain the normal force, the displacement, and the evaluation points on the local \(\bar{x}\)-axis. \(L\) is the length of the bar element.
- Theory:
The nodal displacements in global coordinates are given by
\[\mathbf{a}^e = \left[\; u_1\;\; u_2\;\; u_3\;\; u_4 \;\right]^T\]The transpose of \(\mathbf{a}^e\) is stored in
ed. The nodal displacements in local coordinates are given by\[\mathbf{\bar{a}}^e = \mathbf{G} \mathbf{a}^e\]where the transformation matrix \(\mathbf{G}\) is defined in
bar2ge. The displacements associated with bar action are determined as\[\begin{split}{\mathbf{\bar{a}}}^e_{\text{bar}} = \left[ \begin{array}{r} \bar{u}_1 \\ \bar{u}_3 \end{array}\right]\end{split}\]The displacement \(u(\bar{x})\) and the normal force \(N(\bar{x})\) are computed from
\[u(\bar{x}) = {\mathbf{N}} \mathbf{\bar{a}}^e_{\text{bar}}\]\[N(\bar{x}) = D_{EA} \mathbf{B} \mathbf{\bar{a}}^e_{\text{bar}}\]where
\[\mathbf{N} = \left[\begin{array}{rr} 1 & \bar{x} \end{array}\right] \mathbf{C}^{-1} = \left[\begin{array}{rr} 1-\frac{\bar{x}}{L} & \frac{\bar{x}}{L} \end{array}\right]\]\[\mathbf{B} = \left[\begin{array}{rr} 0 & 1 \end{array}\right] \mathbf{C}^{-1} = \frac{1}{L}\left[\begin{array}{rr} -1 & 1 \end{array}\right]\]where \(D_{EA}\) and \(L\) are defined in
bar2geand\[\begin{split}\mathbf{C}^{-1} = \left[ \begin{array}{rr} 1 & 0 \\ -\frac{1}{L} & \frac{1}{L} \end{array}\right]\end{split}\]An updated value of the axial force is computed as
\[Q_{\bar{x}} = N(0)\]
bar3e¶
Ke = bar3e(ex, ey, ez, ep)
[Ke, fe] = bar3e(ex, ey, ez, ep, eq)
- Description:
bar3eprovides the global element stiffness matrix \({\mathbf{K}}^e\) for a three dimensional bar element.The input variables
ex\(= [x_1 \;\; x_2]\) \(\qquad\)ey\(= [y_1 \;\; y_2]\) \(\qquad\)ez\(= [z_1 \;\; z_2]\) \(\qquad\)ep\(= [E \; A]\)supply the element nodal coordinates \(x_1\), \(y_1\), \(z_1\), \(x_2\), \(y_2\), and \(z_2\), the modulus of elasticity \(E\), and the cross section area \(A\).
The element load vector
fecan also be computed if a uniformly distributed axial load is applied to the element. The optional input variableeq\(= [q_{\bar{x}}]\)contains the distributed load per unit length, \(q_{\bar{x}}\).
- Theory:
The element stiffness matrix \(\mathbf{K}^e\), stored in
Ke, is computed according to\[\mathbf{K}^e = \mathbf{G}^T \; \bar{\mathbf{K}}^e \; \mathbf{G}\]where
\[\begin{split}\bar{\mathbf{K}}^e = \frac{D_{EA}}{L} \begin{bmatrix} 1 & -1 \\ -1 & 1 \end{bmatrix} \qquad \mathbf{G} = \begin{bmatrix} n_{x\bar{x}} & n_{y\bar{x}} & n_{z\bar{x}} & 0 & 0 & 0 \\ 0 & 0 & 0 & n_{x\bar{x}} & n_{y\bar{x}} & n_{z\bar{x}} \end{bmatrix}\end{split}\]where the axial stiffness \(D_{EA}\) and the length \(L\) are given by
\[D_{EA} = EA \qquad L = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2 + (z_2 - z_1)^2}\]and the transformation matrix \(\mathbf{G}\) contains the direction cosines
\[n_{x\bar{x}} = \frac{x_2 - x_1}{L} \qquad n_{y\bar{x}} = \frac{y_2 - y_1}{L} \qquad n_{z\bar{x}} = \frac{z_2 - z_1}{L}\]The element load vector \(\mathbf{f}_l^e\), stored in
fe, is computed according to\[\mathbf{f}_l^e = \mathbf{G}^T \; \bar{\mathbf{f}}_l^e\]where
\[\begin{split}\bar{\mathbf{f}}_l^e = \frac{q_{\bar{x}} L}{2} \begin{bmatrix} 1 \\ 1 \end{bmatrix}\end{split}\]
bar3s¶
es = bar3s(ex, ey, ez, ep, ed)
es = bar3s(ex, ey, ez, ep, ed, eq)
[es, edi] = bar3s(ex, ey, ez, ep, ed, eq, n)
[es, edi, eci] = bar3s(ex, ey, ez, ep, ed, eq, n)
- Description:
bar3scomputes the normal force in a three dimensional bar element (seebar3e).The input variables
ex,ey, andepare defined inbar3eand the element nodal displacements, stored ined, are obtained by the functionextract_ed. The number of evaluation points for section forces and displacements are determined byn. Ifnis omitted, only the ends of the bar are evaluated.The output variables
es\(= \begin{bmatrix} N(0) \\ N(\bar{x}_2) \\ \vdots \\ N(\bar{x}_{n-1}) \\ N(L) \end{bmatrix}\) \(\qquad\)edi\(= \begin{bmatrix} u(0) \\ u(\bar{x}_2) \\ \vdots \\ u(\bar{x}_{n-1}) \\ u(L) \end{bmatrix}\) \(\qquad\)eci\(= \begin{bmatrix} 0 \\ \bar{x}_2 \\ \vdots \\ \bar{x}_{n-1} \\ L \end{bmatrix}\) \(\qquad\)contain the normal force, the displacement, and the evaluation points on the local \(\bar{x}\)-axis. \(L\) is the length of the bar element.
- Theory:
The nodal displacements in global coordinates are given by
\[\mathbf{a}^e = \begin{bmatrix} u_1 & u_2 & u_3 & u_4 & u_5 & u_6 \end{bmatrix}^T\]The transpose of \(\mathbf{a}^e\) is stored in
ed.The nodal displacements in local coordinates are given by
\[\mathbf{\bar{a}}^e = \mathbf{G} \mathbf{a}^e\]where the transformation matrix \(\mathbf{G}\) is defined in
bar3e.The displacement \(u(\bar{x})\) and the normal force \(N(\bar{x})\) are computed from
\[u(\bar{x}) = \mathbf{N} \mathbf{\bar{a}}^e + u_p(\bar{x})\]\[N(\bar{x}) = D_{EA} \mathbf{B} \mathbf{\bar{a}}^e + N_p(\bar{x})\]where
\[\mathbf{N} = \begin{bmatrix} 1 & \bar{x} \end{bmatrix} \mathbf{C}^{-1} = \begin{bmatrix} 1-\frac{\bar{x}}{L} & \frac{\bar{x}}{L} \end{bmatrix}\]\[\mathbf{B} = \begin{bmatrix} 0 & 1 \end{bmatrix} \mathbf{C}^{-1} = \frac{1}{L} \begin{bmatrix} -1 & 1 \end{bmatrix}\]\[u_p(\bar{x}) = -\frac{q_{\bar{x}}}{D_{EA}} \left( \frac{\bar{x}^2}{2} - \frac{L\bar{x}}{2} \right)\]\[N_p(\bar{x}) = -q_{\bar{x}} \left( \bar{x} - \frac{L}{2} \right)\]where \(D_{EA}\), \(L\), \(q_{\bar{x}}\) are defined in
bar3eand\[\begin{split}\mathbf{C}^{-1} = \begin{bmatrix} 1 & 0 \\ -\frac{1}{L} & \frac{1}{L} \end{bmatrix}\end{split}\]