bar1sΒΆ
es = bar1s(ex, ep, ed)
es = bar1s(ex, ep, ed, eq)
[es, edi] = bar1s(ex, ep, ed, eq, n)
[es, edi, eci] = bar1s(ex, ep, ed, eq, n)
- Description:
bar1scomputes the normal force in the one dimensional bar elementbar1e.The input variables
exandepare defined inbar1eand the element nodal displacements, stored ined, are obtained by the functionextract_ed. If distributed load is applied to the element, the variableeqmust be included.The number of evaluation points for normal force and displacement are determined by
n. Ifnis omitted, only the ends of the bar are evaluated.The output variables
es\(= \begin{bmatrix} N(0) \\ N(\bar{x}_2) \\ \vdots \\ N(\bar{x}_{n-1}) \\ N(L) \end{bmatrix}\) \(\qquad\)edi\(= \begin{bmatrix} u(0) \\ u(\bar{x}_2) \\ \vdots \\ u(\bar{x}_{n-1}) \\ u(L) \end{bmatrix}\) \(\qquad\)eci\(= \begin{bmatrix} 0 \\ \bar{x}_2 \\ \vdots \\ \bar{x}_{n-1} \\ L \end{bmatrix}\)contain the normal force, the displacement, and the evaluation points on the local \(\bar{x}\)-axis. \(L\) is the length of the bar element.
- Theory:
The nodal displacements in local coordinates are given by
\[\begin{split}\mathbf{\bar{a}}^e = \begin{bmatrix} \bar{u}_1 \\ \bar{u}_2 \end{bmatrix}\end{split}\]The transpose of \(\mathbf{\bar{a}}^e\) is stored in
ed.The displacement \(u(\bar{x})\) and the normal force \(N(\bar{x})\) are computed from
\[u(\bar{x}) = \mathbf{N} \mathbf{\bar{a}}^e + u_p(\bar{x})\]\[N(\bar{x}) = D_{EA} \mathbf{B} \mathbf{\bar{a}}^e + N_p(\bar{x})\]where
\[\mathbf{N} = \begin{bmatrix} 1 & \bar{x} \end{bmatrix} \mathbf{C}^{-1} = \begin{bmatrix} 1 - \frac{\bar{x}}{L} & \frac{\bar{x}}{L} \end{bmatrix}\]\[\mathbf{B} = \begin{bmatrix} 0 & 1 \end{bmatrix} \mathbf{C}^{-1} = \frac{1}{L} \begin{bmatrix} -1 & 1 \end{bmatrix}\]\[u_p(\bar{x}) = -\frac{q_{\bar{x}}}{D_{EA}} \left( \frac{\bar{x}^2}{2} - \frac{L\bar{x}}{2} \right)\]\[N_p(\bar{x}) = -q_{\bar{x}} \left( \bar{x} - \frac{L}{2} \right)\]in which \(D_{EA}\), \(L\), and \(q_{\bar{x}}\) are defined in
bar1eand\[\begin{split}\mathbf{C}^{-1} = \begin{bmatrix} 1 & 0 \\ -\frac{1}{L} & \frac{1}{L} \end{bmatrix}\end{split}\]